The area of the ellips `(x^(2))/( 9) + ( y^(2))/( 4) = 1 ` is `"…............."`

The eccentricity of the ellipes (x ^(2))/(36)+ (y^(2))/(16) =1 is

The eccentricity of the ellipes (x ^(2))/(36)+ (y^(2))/(16) =1 is

Area of the ellipse x^(2)/9+y^(2)/4=1 is

What is the area of the ellipse 4x^(2) + 9y^(2) = 1 .

Find area of the ellipse 4x ^(2) + 9y ^(2) = 36.

If the foci of the ellips (x^(2))/( 25)+ ( y^(2))/( 16) =1 and the hyperbola (x^(2))/(4) - ( y^(2))/( b^(2) ) =1 coincide ,then b^(2)=

If the foci of the ellips (x^(2))/( 25)+ ( y^(2))/( 16) =1 and the hyperbola (x^(2))/(4) - ( y^(2))/( b^(2) ) =1 coincide ,then b^(2)=

A hyperbola passes through a focus of the ellips (x^(2))/(169) +(y^(2))/( 25) =1 . Its transverse and conjugates axes coincide respectively with the major and minor axes of the ellips The product of eccetricities is 1. Then the equation of the hyperbola is

Area of the regiion bounded by (x^2 )/(16) +(y^2)/(9) = 4

Find the area of the smaller region bounded by the ellipse (x^(2))/(9) + (y^(2))/(4) = 1 and the line (x)/(3) + (y)/(2) = 1