If `x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta,` then `(dy)/(dx)`=

Find (dy)/(dx) : x=2 cos theta- cos^(2) theta and y=2 sin theta- sin 2theta Show that (dy)/(dx)= -1 " when " theta = (pi)/(2)

If x=2cos theta-cos2 theta and y=2sin theta-sin2 theta then prove that (dy)/(dx)=tan((3 theta)/(2))

If x=2cos theta-cos 2theta and y=2sin theta-sin 2 theta , then prove that (dy)/(dx)=tan((3theta)/(2))

If x=2cos theta-cos2 theta and y=2sin theta-sin2 theta, prove that (dy)/(dx)=tan((3 theta)/(2))

If x=cos theta-cos 2theta and y=sin theta-sin2theta , then find (dy)/(dx) .

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta . then find dy/dx

If x=2cos theta -cos 2theta ,y=2sin theta -sin 2theta ,then (dy)/(dx) =

If =2cos theta-cos2 theta and y=2sin theta-sin2 theta Prove that (dy)/(dx)=tan((3 theta)/(2))