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In a carnot engine, temperature of the s...

In a carnot engine, temperature of the source is 500 K and that of the sink is 375 K. If the engine absorbs 600 k cal heat from the source per cycle, find (i) its efficiency (ii) work done per cycle, (iii) heat released in the sink. (J = 4.2 J/cal)

Text Solution

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`T_1`=500 K, `T_2`=375 K
`Q_1`=600 cal
(1)`eta=1-T_2/T_1=1-375/500=(500-375)/500`
`eta=1/4`=0.25%
(2)`eta=W/Q_1`
`therefore W=etaQ_1=1/4xx6xx10^5=1.5xx10^5` cal
`W=1.5xx4.2xx10^5=6.3xx10^5`J
(3)`W=Q_1-Q_2`
`therefore Q_2=Q_1-W=6xx10^5-1.5xx10^5`
`Q_2=4.5xx10^5` cal
`Q_2`=4.5 K Cal
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