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An ideal gas at temperature T1 is compre...

An ideal gas at temperature `T_1` is compressed to 32th of its original volume, then its temperature `T_2` will be _____ `(gamma=1.4)`

Text Solution

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For an adiabatic process,
`T_1V_1^(gamma-1)=T_2V_2^(gamma-1)`
`therefore T_2=T_1(V_1/V_2)^(gamma-1)`
`=T_1(V_1/(V_1//32))^(gamma-1)=T_1(32)^(1.4-1)`
`=T_1xx(2^5)^(2//5)`
`=T_1xx4`
`=4T_1`
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