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Under an adiabatic process, the volume o...

Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently, the mean collision time between the gas molecules changes from `tau_(1) " to" tau_(2)`. If `(C_(P))/(C_(V))= gamma` for this gas, then a good estimate for `(tau_(2))/(tau_(1))` is given by

A

`(1)/(2)`

B

2

C

`((1)/(2))^(gamma)`

D

`((1)/(2))^((gamma)/(2) +1)`

Text Solution

Verified by Experts

Relaxaation time `tau prop (V)/(sqrtT) and T prop (1)/(V^(gamma-1))`
`:. tau prop V^(1 + (gamma-1)/(2))`
`:. tau= V^((1 + gamma)/(2))`
`:. (tau_(1))/(tau_(i)) = ((2V)/(V))^((1 + gamma)/(2)) = (2)^((1 + gamma)/(2))`
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