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A small hole of area of cross-section 2m...

A small hole of area of cross-section `2mm^(2)` is present near of the bottom of a fully filled open tank of height 2m. Taking `g= 10 m//s^(2)`, the rate of flow of water through the open hole would be nearly:

A

`6.4 xx 10^(-6) m^(3)//s`

B

`12.6 xx 10^(-6) m^(3)//s`

C

`8.9 xx 10^(-6) m^(3)//s`

D

`2.23 xx 10^(-6) m^(3)//s`

Text Solution

Verified by Experts

The correct Answer is:
B
Velocity of water coming out of hole, `v= sqrt(2gh)`
Time rate of flow of water, = Av
`=A sqrt(2gh)`
`=(2 xx 10^(-6)) (2 xx 10 xx 2)^(½)`
`=4 sqrt10 xx 10^(-6)`
`=4 xx 3.16 xx 10^(-6)`
`=12.64 xx 10^(-6)`
`~~ 12.6 xx 10^(-6) m^(3)//s`
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