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consider a uniform electric field overs...

consider a uniform electric field ` oversetto E =3xx 10^(3) hati N//C `
What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane?
(b) What is the flux through the same square if if the normal to its plane makes a `60^(@) ` angle with the x-axis?

Text Solution

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Here ` oversetto E =3xx 10^(3) hat I N//C `
As side of square =10 cm =0.1m, hence surface area `S= ( 0.1 ) ^(2) =0.01 m^(2) `. The plane of surface area being parallel to y= plane, hence `oversetto S = 0.01 hati m^(2) `
` therefore ` Electric flux of the field ` phi_E = oversetto E. oversetto S= (3xx10 ^(3) hati) .(0.01 hati ) =30 N m^(2) C^(-1) `
(b) When normal to the plane of surface area makes an angle of ` 60^(@) ` with the x-axis flux is given by
` phi_E=oversetto.oversettoS =E S cos theta =3xx 10^(3) xx 0.01 xx cos 60^(@) `
` " " = 15 Nm^(2) C^(-1) `
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