Two large, thin metal plates are parallel and close to each other , On their inner faces, the plates have surface charges densities of opposite signs and of magnitude `17.0 xx10 ^(-22) C//m^(2) `.What is `overset to E` :
in the outer region of the first plate,
(b) in the outer region of the second plate,
(c) between the plates?

Explanation

Let A and B be two large, thin metal plates held parallel and close to each other as shown in surface density of charges on `A sigma =+17.0 xx 10^(-22) C//m^(2)`. And surface density of charges on ` B, -sigma =-17.0 xx 10 ^(-22) C//m^(2) `
At any point K in the outer region of first plate A, we have
` |oversetto (E_A) | = |oversetto (E_B)| =(sigma )/(2in _0) ` but their directions are mutually opposite,
Hence ` " "Oversetto (E_k) =overset to (E_A) +overset to (E_B) =overset to 0`
(b) Let A and B be two large, thin metal plates held parallel and close to each other as shown in surface density of charges on `A sigma =+17.0 xx 10^(-22) C//m^(2)`. And surface density of charges on ` B, -sigma =-17.0 xx 10 ^(-22) C//m^(2) `
Again at a point M in the outer region of the second plate, net electric field is zero
(c) Let A and B be two large, thin metal plates held parallel and close to each other as shown in surface density of charges on `A sigma =+17.0 xx 10^(-22) C//m^(2)`. And surface density of charges on ` B, -sigma =-17.0 xx 10 ^(-22) C//m^(2) `
At a point N between the plates A and B , `overset (E_A) and oversetto (E_B) ` are equal in magnitude and both are directed in same direction and are, therefore, added up, hence net electric field is given by,
` oversetto E =oversetto (E_A) +overset to (E_B) =(sigma )/(2in _0) +(sigma)/(2in _0) =(sigma)/(in_0) =(1.70xx10^(-22))/(8.85xx10^(-12)) =1.9 xx10^(-10) NC^(-1) `