Answer questions on the basis of your un...

Answer questions on the basis of your understanding of the following paragraph and the related studied concept.
Electric flux, in general , through any surface is defined as per relation:
`phi_E= int oversetto E. oversetto (ds) ` , where integration has to be performed over the entire surface through which flux is required. The surface under consideration may be a closed one or an open surface. When flux through a closed surface is required we use a small circular sign on the integration symbol. Thus flux over a closed surface `oint E= oint oversetto E. oversetto (ds) . ` it is customary to take the outward normal as positive in this case.
A German physicist Gauss established a fundamental law to find electric flux over a closed surface. As per Gauss' law , the flux of the net electric field through a closed surface equals the net charge enclosed by the surface divided by `in_0 . `Mathematically `oint oversetto (E) . oversetto (ds) =(1)/( in_0) [q_(en) ] ` , where `q_(cn) ` is the net charge enclosed within the surface. It is possible to derive Gauss' law from Coulomb's laws. Gauss' law can be applied to obtain electric field at a point due to continuous charge distribution for a number of symmetric charge configurations.
A charge q is enclosed by a Gaussian spherical surface of raidus R. If the radius is doubled then the electric flux will.

be doubled

increases four times

be reduced to half.

remain the same.

Verified by Experts

The correct Answer is:

For give enclosed charges net electric flux is independent of the surface area.

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Answer questions on the basis of your understanding of the following paragraph and the related studied concept. Electric flux, in general , through any surface is defined as per relation: phi_E= int oversetto E. oversetto (ds) , where integration has to be performed over the entire surface through which flux is required. The surface under consideration may be a closed one or an open surface. When flux through a closed surface is required we use a small circular sign on the integration symbol. Thus flux over a closed surface oint E= oint oversetto E. oversetto (ds) . it is customary to take the outward normal as positive in this case. A German physicist Gauss established a fundamental law to find electric flux over a closed surface. As per Gauss' law , the flux of the net electric field through a closed surface equals the net charge enclosed by the surface divided by in_0 . Mathematically oint oversetto (E) . oversetto (ds) =(1)/( in_0) [q_(en) ] , where q_(cn) is the net charge enclosed within the surface. It is possible to derive Gauss' law from Coulomb's laws. Gauss' law can be applied to obtain electric field at a point due to continuous charge distribution for a number of symmetric charge configurations. What is the electrical flux through a cube of side 'a' if a point charge 'q' is placed at one of its vertices?

`(q)/(in_0) `

` (2q)/(in_0) `

` (q)/(8in_0) `

` (q)/(in_0). 6a^(2) `

zero

`EL^(2) `

` (EL^(2))/( 2 in _0) `

` (EL^(2))/(2) `

` + 2.26 xx 10^(5) V m `

` +7.91 xx 10 ^(5) V m`

` -2.26 xx 10 ^(5) V m `

` +1.36 xx 10 ^(-6) V m`