An electrons is moving round the nucleus of a hydrogen atoms in a circular orbit of radius r. The coulomg force ` oversetto F ` between the two is (where K `=( 1)/( 4pi in _0)) `

Options

A. ` K(e^(2))/(r^(3)) oversetto r `
B. ` k(e^(2))/( r^(2)) oversetto r `
C. ` -k(e^(2))/( r^(3)) oversetto r `
D. ` -k(e^(2))/( r^(2)) oversetto r `

Answer

C

Explanation

Force F=`( kq_1kq_2)/(r^(3)) oversettor =(ke^(2))/(r^(3)) oversetto r.` Here-ve sign shows that force between hydrogen nucleus i.e. proton and the electron is attractive in nature.