ABC is an equilateral triangle. Charged of +q are placed at each corner. The electric field at O will be
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Options

A. ` (1)/( 4pi in _0) .(q)/(r^(2))`
B. ` (1)/(4pi in _0).(q)/® `
C. `0`
D. ` (1)/(4pi in _0) .(3q)/(r^(2))`

Answer

C

Explanation

Net field at O is zero because `E_A=E_B=E_C ` and the three fields are mutually inclined at ` 120^(@) ` each and their resultant is zero.