Two large metal plates of area `6.0 m^(2) ` face each other . The plates are 3 cm apart and carry equal and opposite charges on their inner surfaces. If electric field at a point between the plates is ` 5 xx 10 ^(4) NC ^(-1) ,` then calculate the magnitude of charge on each plates.

Explanation

Let magnitude of charge on the inner surface of each plate be Q .
It is given that A = `6.0 m^(2) and E = 5 xx 10^(4) C ^(-1) `
At point P between the two plates , electric field due to both plates is equal and directed in same direction ,i.e.
` oversetto (E_1) =oversetto (E_2) =(sigma)/( 2 in _0) " " ` [From plate 1 towards plates 2 ]
` therefore ` Net electric field at point P
` " " E=E_1 +E_2 =(sigma )/( in_0) = (Q)/( in_0A ) `
`rArr " "Q= in _0 AE = 8.85 xx 10 ^(-12) xx 6.0 xx 5 xx 10 ^(4) `
` " " =2.655 xx10 ^(-6) C or 2.66 muC `
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