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A charge Q is divided into two parts of ...

A charge Q is divided into two parts of q and (Q-q) . If the Coulombian repulsion between them, when they are separated by a finite distance, is maximum the ratio ` (q)/(Q) ` should be ____________

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The correct Answer is:
`1: 2`
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Knowledge Check

  • A charge Q is divided into two parts q_(1)andq_(2) such that they experience maximmum force of repulsion when separated by cetain distance .The ratio of Q q_(1)andq_(2) is

    A
    `1:1:2`
    B
    `1:2:2`
    C
    `2:2:1`
    D
    `2:2:1`
  • Two point charges Q and - Q //4 are separated by a distance X . Then .

    A
    potential is zero at a point on the axis which is ` x//3` on the right side of the cahrge `-q//4`
    B
    potential is zero at a point on the axis which is `x//5` on the left side fo the charge `- Q//4`
    C
    electric field is zero at a point on the axis which is at a distance `x` on the right side fo the charge `- Q//4`
    D
    there exist two points on the axis where electric field is zero.
  • A charge Q is divided into two parts. Charge on each part is q. Also, Q//q=2 . What is the Columbic force between two charges q and q when both parts are placed certain distance apart?

    A
    Force is equal in magnitude for both but opposite in direction
    B
    Force is dependent on the medium in which charges are placed
    C
    Force is maximum irrespective of medium in which charges are placed
    D
    None of the above
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