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A charge of 8 mC is located at the origi...

A charge of 8 mC is located at the origin. Calculate the work done in taking a small charge of `-2 xx 10^(-9)C` from a point P(0,0,3 cm) to a point Q10,4 cm, 0) via a point R(0,6 cm, 9 cm).

Text Solution

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As electrostatic field is a conservative field hence work done in taking a small charge from point P to Q is independent of the path followed.
As q = 8 mC `= 8 xx 10^(-3) C, q_0 = -2 xx 10^(-9) C`
At point P, `r_1 = 3 cm = 0.03 m` and at point Q,`r_2 = 4 cm = 0.04 m`
`:.` Work done `W = q_0 (V_2 - V_1) = q_0 1/(4pi epsi_0) .q[1/r_2-1/r_1] = (q_0q)/(4pi epsi_0) [ 1/r_2 - 1/r_1]`
`:. W = 9 xx 10^9 xx (-2 xx 10^(-9))xx (8 xx 10^(-3)) [ 1/0.04 - 1/0.03] = 1.2 J`
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A charge of 8 mC is located at the origin. Calculate the work done in taking a small charge of -2xx10^(-9)C from a point P (0,0,3 cm) to a point Q (0,4 cm, 0) via a point R (0,6 cm, 9cm).

A charge of 8 mC is located at the origin. Calculate the work done in taking a small charge of -2xx10^(-9) from a point P(0,0,3cm) to a point Q (0,4cm,0) via a point R(0,6cm,9cm).

Knowledge Check

  • Calculate the work done in taking a charge - 2 xx 10^(-9) C from A to B via C (in diagram )

    A
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    B
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    C
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    D
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  • In the question number 4, work done in bringing a charge of 4xx10^(-9) C form infinity to that point is

    A
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    B
    `1.8xx10^(-4)J`
    C
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    D
    `4.1xx10^(-5)J`

  • As per this diagram a point charge +q is placed at the origin O . Work done in taking another point charge -Q from the point A(0, a) to another point B(a, 0) along the staight path AB is:

    A
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    B
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    C
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    D
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