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Define angle of dip. Deduce the relation...

Define angle of dip. Deduce the relation connecting angle of dip and horizontal component of earth's magnetic field at a place.

Text Solution

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In fig. CDAB is the magnetic meridian . Magnetic field to earth `vecB_E` at the place is inclined at an angle, equal to angle of dip , `delta` from horizontal direction along magnetic meridian . Hence , horizontal component `vecB_H` of earth.s magnetic field will be given by
`B_H = B_E . cos delta ` or `(B_H)/(B_E)= cos delta`
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What is the angle of dip at a given place on the earth if both vertical and horizontal components of the earth's magnetic field are equal ?

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Knowledge Check

  • The angle of dip at a certain place where the horizontal and vertical components of the earth's magnetic field are equal is

    A
    `30^(@)`
    B
    `75^(@)`
    C
    `60^(@)`
    D
    `45^(@)`

  • Our earth behaves as it has a powerful magnet within it. The value of magnetic field on the surface of earth is a few tenth of gauss (1G = 10^(-4) T) There are three elements of Earth’s magnetism (i) Angle of declination (ii) Angle of dip (iii) Horizontal component of Earth’s magnetic field. In the magnetic meridian of a certain place, the horizontal component of Earth’s magnetic field is 0.6 G and the dip angle is 53^@ . The value of vertical component of earth's magnetic field at this place is

    A
    0.8 G
    B
    0.6 G
    C
    1.0 G
    D
    2.0 G

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