Consider a triangle PQR in which the relation `QR^(2)+PR^(2)=5PQ^(2)` holds. Let G be the point of intersection of medians PM and QN. Then `angleQGM` is always

Construct a triangle PQR, in which PR = 6 cm and PQ = QR = 6.8 cm. Mark S the mid-point of PQ.

Construct a triangle PQR in which QR = 6 cm, angleQ = 60^@ and PR - PQ = 2 cm.

Construct a triangle PQR in which QR = 6cm, angleQ=60^@ and PR – PQ = 2cm.

Construct a triangle PQR in which QR = 6cm, angleQ=60^@ and PR – PQ = 2cm.

In the figure, angleQPR = anglePQR and M and N are respectively on sides QR and PR such that QM = PN. Prove that OP=OQ, where O is the point of intersection of PM and QN.

PQR is a triangle such that PQ = PR. RS and QT are the median to the sides PQ and PR respectively. If the medians RS and QT intersect at right angle, then what is the value of "(PQ/QR)"^(2) ?

In triangle PQR , M is the midpoint of side QR. If PQ=11, PR=17 and QR=12, then find PM.