At what altitude, the acceleration due to gravity reduces to half of its value as that on the surface of the earth ? Take radius of earth as `6.410^(6)` m, g on the surface of the earth as `9.8 m//s^(2)`.

At what altitude , the acceleration due to gravity reduces to half of its value as that on the surface of the earth ? Take radius of earth as 6 . 4 xx 10^(6) m , g on the surface of the earth as 9.8 m//s ^(2) .

At what altitude, the acceleration due to gravity reduces to one fourth of its value as that on the surface of the earth ? Take radius of earth as 6.4 xx 10^(6) m , g on the surface of the earth as 9.8 ms^(-2) .

At what altitude, the acceleration due to gravity reduces to one fourth of its value as that on the surface of the earth ? Take radius of earth as 6.4 xx 10^(6) m , g on the surface of the earth as 9.8 ms^(-2) .

At what height from Earth's surface the acceleration due to gravity becomes 20% of its value on the surface of earth. [Radius of earth = 6,400 km.]

At what altitude will the acceleration due to gravity be 25% of that at the earth’s surface (given radius of earth is R) ?

How much below the surface of Earth does the acceleration due to gravity become 70% of its value on the surface of Earth. Radius of Earth = 6.4 xx 10^(6) m .

The acceleration due to gravity about the earth's surface would be half of its value on the surface of the earth at an altitude of ( R = 4000 mile )

At what height above the earth surface, the acceleration due to gravity will be half that on the surface of earth ? Suppose R is the radius of earth.

At what depth from the surface of the earth, the acceleration due to gravity will be half the value of g on the surface of the earth ?

At what depth from the surface of the earth, the acceleration due to gravity will be half the value of g on the surface of the earth ?