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The probabilty of hitting a target is 1/...

The probabilty of hitting a target is 1/3. The least number of times to fire so that the probability of hitting the larget atleast once is more than `90%` is

A

4

B

5

C

6

D

7

Text Solution

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The correct Answer is:
C
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AAKASH SERIES-RANDOM VARIABLE -EXERCISE - II
  1. The mean and variance of a random variable X having binomial distribut...

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  2. The least number of times a fair coin must be tossed so that the proba...

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  3. The probabilty of hitting a target is 1/3. The least number of times t...

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  4. The mean and variance of a random variable X having a binomial distrib...

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  5. In a binomial distribution, mean = 25, variance = 20 then P(X le 100)=

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  6. If the mean and variance of a binomial variable X are 2 and 1 respecti...

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  7. X is a binomial variate with parameters n=6 and p. If 4P(X=4)=P(X=2), ...

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  8. For a binomial variate X if n=5, and P(X=1)=8P(X=3), thenp=

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  9. X follows a binomial distribution with parameters n and p where 0 lt p...

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  10. Suppose X is binomial distribution with parameters n = 100 and p = 1/...

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  11. Suppose X is a binomial distribution with parameters n = 100 and p=(1)...

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  12. A coin is tossed any number of times until a head appears. If x donote...

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  13. A fair coin is tossed n times. Let x be random variable denoting the n...

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  14. When a coin is tossed n times, if the probability for getting 6 heads ...

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  15. One hundred identical coins each with probability p showing up heads a...

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  16. A die is rolled 3 times. If getting a one is considered as a success, ...

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  17. An unbiased die is tossed 6 times. The mean of number odd numbers is

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  18. In a binomial distribution B(n,p=(1)/(4)), if the probability of at le...

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  19. A die is thrown (2n + 1) times. The probability of getting 1 or 3 or 4...

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  20. If X is a binomial variate with n = 7 and P(X=3)=P(X=4) then P(X=5)=

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