The mean and the variance in a bionomial distribution of found to be 2 and 1 respectively. The probability P(X=0) is

The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probability of 2 successes is

The mean and the variance of a binomial distribution are 4 and 2 respectively.Then the probability of 2 success is

The mean and the variance of a binomial distribution are 4 and 2 respectively. Then, the probability of 2 successes is

The mean and the variance of a binomial distribution are 4 and 2 respectively.Then the probability of 3 successes is

If the mean and the variance of a binomial distribution are 2 and 1 respectively , then the probability of atleast one success is

IF the mean and the variance of a binomial distribution are 4 and 3 respectively ,then the probability of six successes is

IF the mean and the variance of a binomial distribution are 4 and 3 respectively , then the probability of six successes is

The mean and variance of a binomial distribution are 4 and 2 respectively . Then the probability of 2 successes is :