[" (a) "3.6+6.9+9.12+......+3n(3n+3)],[=3n(n+1)(n+2)]

By the Principle of Mathematical Induction, prove the following for all n in N : 3.6+6.9+9.12+......+ 3n(3n+3) = 3n(n + 1) (n + 2) .

1,6+2.9+3.12+....+n(3n+3)=

Prove by the principle of mathematical induction, that 3xx6+6xx9+9xx12+....+(3n)xx(3n+3)=3n(n+1)(n+2)

Prove by the principle of mathematical induction, that 3xx6+6xx9+9xx12+....+(3n)xx(3n+3)=3n(n+1)(n+2)

Prove the following by using the Principle of mathematical induction AA n in N 3.6+6.9+9.12+……+3n(3n+3)=3n(n+1)(n+2)

Prove the following by using the principle of mathematical induction for all n in N 3 xx 6 + 6 xx 9 + 9 xx 12 + …..+ (3n)(3n+3) = 3n(n+1)(n+2)

By method of induction, prove that 1.6 + 2.9 + 3.12 +... +to n terms = n(n +1 )(n+2) for all n in N .

1.3+2.4+3.5+....+n(n+2)=(n(n+1)(2n+7))/(6)

1.2+2.3+3.4+.........+n(n+1)=(1)/(3)n(n+1)(n+3)