Helium nuclei combine to form an oxygen nucleus. The energy released in the reaction is if `m_(O)=15.9994 "amu"` and `m_(He)=4.0026 "amu"`

Helium nuclei combines to form an oxygen nucleus. The energy released per nucleon of oxygen nucleus is if m_(0)=15.834 amu and m_(He)=4.0026 amu

A slow neutron strikes a nucleus of ._(92)U^(235) splitting it into lighter nuclei of barium and krypton and releasing three neutrons. Write the corresponding nuclear reaction. Also calculate the energy released on this reaction Given m(._(92)U^(235))=235.043933 "amu" m(._(0)n^(1))=1.008665 amu m(._(56)Ba^(141))=140.917700 "amu" m(._(36)Kr^(92))=91.895400 amu

The energy released in nuclear reactions corresponding to 1 a.m.u. is about :

If a star can convert all the He nuclei completely into oxygen nuclei. The energy released per oxygen nuclei is (Mass of the helium nucleus is 4.0026 amu and mass of oxygen nucleus is 15.9994 amu)

If a star can convert all the He nuclei completely into oxygen nuclei. The energy released per oxygen nuclei is (Mass of the helium nucleus is 4.0026 amu and mass of oxygen nucleus is 15.9994 amu)