A proton is projected with a velocity of `3xx10^(6) m//s` perpendicular to a uniform magnetic field of `0.6 T`.Find the acceleration of the proton.mass of proton`=5/3xx10^(-27) kg`

A proton is projected with a velocity of 3X10^6 m s ^(-1) perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

A proton is projected with a velocity of 3X10^6 m s ^(-1) perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

A proton is projected with a velocity of 3X10^6 m s ^(-1) perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

A neutron and a proton both are fired with some speed of 3 xx 10^(6) m/s perpendicular to a uniform magnetic field of 1 T. What will be the individual acceleration of particles! Consider that only magnetic force is acting on the particles.

A proton of velocity of 10^8 cms^-1 is moving perpendicular to a uniform magnetic field of 10 kilogauss. What is the sideway force actig on the proton of charge e = 4.8 xx 10^10 e.s.u.?

A proton is projected with a velocity 10^(7)ms^(-1) , at right angles to a uniform magnetic field of induction 100mT . The time ( in second ) taken by the proton to traverse 90^(@) are is : ( Mass of proton =1.65xx10^(-27)kg an charge of proton =1.6 xx10^(-19)C)