[" Function "f(x)" is defined such that "f(x)={[int_(0)^(x)(5+|1-t|)dt,x>2" then identify the "],[5x+1,x<=2]]

If f(x)={int_(0)^(x)|1-t|dt;x>1,x-(1)/(2);x<=1 then

A Function f(x) satisfies the relation f(x)=e^(x)+int_(0)^(1)e^(x)f(t)dt* Then (a)f(0) 0

A function f(x) satisfies f(x)=sin x+int_(0)^(x)f'(t)(2sin t-sin^(2)t)dt is

Let f(x)=int_(0)^(x)cos((t^(2)+2t+1)/(5))dt0>x>2 then f(x)

A function f is defined by f(x)=int_(0)^(x)(dt)/(1+t^(2)) The normal line to y=f(x) at x=1 has x -intercept equal to X and y -intercept equal to Y then

A continuous function f(x) satisfies the relation f(x)=e^(x)+int_(0)^(1)e^(x)f(t)dt then f(1)=

if f(x) is a differential function such that f(x)=int_(0)^(x)(1+2xf(t))dt&f(1)=e , then Q. int_(0)^(1)f(x)dx=

if f(x) is a differential function such that f(x)=int_(0)^(x)(1+2xf(t))dt&f(1)=e , then Q. int_(0)^(1)f(x)dx=

Let f(x) be a differentiable function such that f(x)=x^(2)+int_(0)^(x)e^(-t)f(x-t)dt then int_(0)^(1)f(x)dx=

if f be a differentiable function such that f(x) =x^(2)int_(0)^(x)e^(-t)f(x-t). dt. Then f(x) =