`sin4theta-sin2theta=cos3theta`

sin4 theta-sin2 theta=cos3 theta

Solve sqrt(3)cos theta-3sin theta=4sin2 theta cos3 theta

One of the general solutions of sqrt(3)cos theta-3sin theta=4sin2 theta cos3 theta is m pi+(pi)/(18),m in Z(m pi)/(2)+(pi)/(6),AA m in Zm(pi)/(3)+(pi)/(18),m in Z none of these

Solve: sin2theta+sin4theta=costheta+cos3theta

Solve: sin2theta+sin4theta=costheta+cos3theta

Sum to n terms the series costheta-sin2theta-cos3theta+sin4theta+cos5theta-……

Sum to n terms the series costheta-sin2theta-cos3theta+sin4theta+cos5theta-……

(sin3 theta-sin theta sin^(2)(2 theta))/(sin theta+sin2 theta cos theta)=cos x then x=

Prove that sin theta+sin2 theta+sin4 theta+sin5 theta=4cos((theta)/(2))cos((3 theta)/(2))sin3 theta