[" Show that "238" th can not spontaneously emit a proton.Given "],[230=238.05079u,quad 237],[720=237,05121uquad _(1)^(1)H=1.00783u]

Show that ""_(92)^(238)U can not spontaneously emit a proton. Given: ""_(92)^(238)U = 238.05079u, ""_(91)^(237)Pa = 237.05121u ""_(1)^(1)H = 1.00783u

Show that ""_(92)^(238)U can not spontaneously emit a proton. Given: ""_(92)^(238)U = 238.05079u, ""_(91)^(237)Pa = 237.05121u ""_(1)^(1)H = 1.00783u

How much energy should be given to uranium to eject one proton from its nucleus? Given _92^238U=238.05079amu _91^237Pa=237.0512 amu _1^1H=1.00783 amu,1mu=931.5MeV

Is it possible for ""_(92)U^(238) spontaneously to emit a proton? Given, atomic mass of ""_(92)U^(238), ""_(91)Pa^(237) and ""_(1)H^(1) is 238.05079 u, 237.05115 u and 1.00783 u respectively.

Show that ._(92)^(230)U does not decay by emitting a neutron or proton. Given: M(._(92)^(230)U)=230.033927 am u, M(._(92)^(230)U)=229.033496 am u , M(._(92)^(229)Pa)=229.032089 am u, M(n)=1.008665 am u m(p)=1.007825 am u .

Show that ._(92)^(230)U does not decay by emitting a neutron or proton. Given: M(._(92)^(230)U)=230.033927 am u, M(._(92)^(230)U)=229.033496 am u , M(._(92)^(229)Pa)=229.032089 am u, M(n)=1.008665 am u m(p)=1.007825 am u .

U^238 emits

We are given the following atomic masses: ._(92)^(238)U=238.05079u ._(2)^(4)He=4.00260u ._(90)^(234)Th=234.04363u ._(1)^(1)H=1.00783u ._(91)^(237)Pa=237.05121u Here the symbol Pa is for the element protactinium (Z=91)