" The number of solutions of the equation "sin x=x^(2)+x

The number of solution of the equation sin x = x^(2) + x + 1

Let the number of solution of the equation sin x=x^(2)-4x+5be lambda. The general solution of the solution 1+tan((lambda^(2)-2 lambda+1)theta)+(2)/(1-tan((lambda^(2)+2 lambda+1)theta))=0

Find the number of solution to the equation sin x = x^(2) + 2x + 1.

The number of solution x of the equation sin (x+x^(2))- sin(x^(2))= sin x in the interval [2,3] is

Am . The number of solutions of the equation (sin x)^(2sin x)=1,in[0,2 pi] is :

Assertion (A) : The number of real solutions of the equation sin x = x^(2) + 3x + 4 is zero Reason (R): -1 le sin x le 1 , AA x in R

Number of solutions(s) of the equation sin x=[x]