A sound has an intensity of `2 xx 10^(-8) W//m^(2)`. Its intensity level in decibels is `(log_(10) 2 = 0.3)`

Four sources of sound each of sound level 10 dB are sounded together in phase , the resultant intensity level will be (log _(10) 2 = 0.3)

Four sources of sound each of sound level 10 dB are sounded together in phase , the resultant intensity level will be (log _(10) 2 = 0.3)

The zero level of intensity of a sound is 10^(-16) wat t //cm^(2) . Calculate intensity level of a sound of intensity 10^(-7)wat t //m^(2) .

The pressure amplitude in a sound wave from a radio receive is 2.0 xx 10^(-3)N//m^(2) and the intensity at a point is 10^(-6)W//m^(2) . If by turning the "Volume" knob the pressure amplitude is increased to 3 xx 10^(-2)N//m^(2) , evalute the intensity.

The intensity of a wave emitted from a small source at a distance 10 m is 20 xx 10^(-3)"Wm"^(-2). What is the intensity at a distance 100 m ?

The intensity level of a sound of intensity of 10^(-12)wat t//cm^(2) is 40 dB. What is the zero level of intensity ?

Find the intensity level of a sound wave in decibles of a sound wave whose intensity is 10^(-10) cm^(-2) . Take zero level of intensity = 10^(-12)Wm^(-2) .