The equation of circle which pass through the points `(2.0), (0.2) `and orthogonal to the circle `2x^2 +2y^2+5x-6y+4=0`

Find the equation of the circle which passes through the points (2,0)(0,2) and orthogonal to the circle 2x^2+2y^2+5x-6y+4=0 .

Find the equation of the circle which passes through the points (2,0)(0,2) and orthogonal to the circle 2x^2+2y^2+5x-6y+4=0 .

Find the equation of the circle which passes through the point (2,0), (0,2) and orthogonally to the circle 2x^2 + 2y^2 + 5x - 6y + 4 = 0 .

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y-7=0 is

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^2+y^2-6x+8=0 and x^2+y^2-2x-2y=7 is

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y=7 is

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^2+y^2-6x+8=0 and x^2+y^2-2x-2y=7 is

A circle S passes through the point (0, 1) and is orthogonal to the circles (x - 1)^2 +y^2=16 and x^2+y^2=1 . Then