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`cos theta" cosec "theta=cot theta`

Find cos theta, if 6 cot theta+2 "cosec" theta= cot theta+5 "cosec" theta .

If sqrt((1+ cos theta )/(1- cos theta ))="cosec " theta + cot theta " then " theta lies in the quadrants

Prove that:- sqrt((1+cos theta) / (1-cos theta)) = cosec theta + cot theta

csc theta(1+cos theta)(csc theta-cot theta)=1

Prove that: ("cosec" theta + cot theta)/("cosec" theta - cot theta) = ("cosec" theta + cot theta )^(2) = 1 + 2 cot^(2) theta + 2 "cosec" theta cot theta .

If cosec theta + cot theta= p , cos theta = ?

((sec theta + tan theta) (1- sin theta))/(cosec theta (1 + cos theta)(cosec theta - cot theta)) is equal to: ((sec theta + tan theta) (1- sin theta))/(cosec theta (1 + cos theta)(cosec theta - cot theta)) बराबर है :

Prove each of the following identities : (i) (1+ cos theta)(1- cos theta)(1+ cot^(2) theta)=1 (ii) "cosec" theta (1+ cos theta)("cosec" theta - cot theta)=1

The inverse of [(-cot theta, cosec theta),(cosec theta,-cot theta)] is

If (cosec theta - cot theta)=2 , the (cosec theta +cot theta) is equal to