`sin^6A+cos^6A+3sin^2A.cos^2A=` (a) 0 (b)1 (c) 2 (d) 3

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sin^(6)A + cos^(6)A + 3sin^(2)A.cos^(2)A=

sin^(6)A+cos^(6)A+3sin^(2)A cos^(2)A=0 b.1c2d.3

2 [ sin x - cos x ]^(4) + 6 [ sin x + cos x ]^(2) + 5 [ sin^(6)x + cos^(6) x ] = ? (a)6 (b)4 (c)3 (d)13

sin ^ (6) A + cos ^ (6) A = 1-3sin ^ (2) A cos ^ (2) A

cos^6A-sin^6A=cos2A(1-1/4sin^2 2A)

Prove that 2 (sin ^ (6) A + cos ^ (6) A) -3 (sin ^ (4) A + cos ^ (4) A) + 1 = 0

2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) is equal to 0 (b) 1 (c) -1 (d) None of these

2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) is equal to (a) 0 (b) 1 (c) -1 (d) None of these

Prove the following : cos^6A-sin^6A = cos2A(1-1/4 sin^2 2A)