Home
Class 11
MATHS
Two perpendicular tangents to the circle...

Two perpendicular tangents to the circle `x^2 + y^2= a^2` meet at P. Then the locus of P has the equation

Promotional Banner

Similar Questions

Explore conceptually related problems

If the tangent from a point p to the circle x^2+y^2=1 is perpendicular to the tangent from p to the circle x^2 +y^2 = 3 , then the locus of p is

If the tangent from a point P to the circle x^(2)+y^(2)=1 is perpendicular to the tangent from P to the circle x^(2)+y^(2)=3 , then the locus of P is

If the tangent from a point p to the circle x^(2)+y^(2)=1 is perpendicular to the tangent from p to the circle x^(2)+y^(2)=3, then the locus of p is

The angle between the two tangents drawn from a point p to the circle x^(2)+y^(2)=a^(2) is 120^(@) . Show that the locus of P is the circle x^(2)+y^(2)=(4a^(2))/(3)

The angle between a pair of tangents from a point P to the circle x^2 + y^2 = 25 is pi/3 . Find the equation of the locus of the point P.

The angle between a pair of tangents from a point P to the circle x^2 + y^2 = 25 is pi/3 . Find the equation of the locus of the point P.

A tangent at a point on the circle x^(2)+y^(2)=a^(2) intersects a concentric circle C at two points P and Q. The tangents to the circle X at P and Q meet at a point on the circle x^(2)+y^(2)=b^(2). Then the equation of the circle is x^(2)+y^(2)=abx^(2)+y^(2)=(a-b)^(2)x^(2)+y^(2)=(a+b)^(2)x^(2)+y^(2)=a^(2)+b^(2)

A tangent to the circle x^(2)+y^(2)=1 through the point (0, 5) cuts the circle x^(2)+y^(2)=4 at P and Q. If the tangents to the circle x^(2)+y^(2)=4 at P and Q meet at R, then the coordinates of R are