Let `omega` be the solution of `x^(3)-1=0` with `"Im"(omega) gt 0`. If a=2 with b and c satisfying `[abc][{:(1,9,7),(2,8,7),(7,3,7):}]=[0,0,0]`, then the value of `3/omega^(a) + 1/omega^(b) + 1/omega^( c)` is equal to

Let a, b, and c be three real numbers satifying [(a, b, c)] [(1,9,7),(8,2,7),(7,3,7)]=[(0,0,0)] Let omega be a solution of x^(3)-1=0 with Im (omega) gt 0 . If a=2 with b and c satisfying (E), then the value of 3/omega^(a)+1/omega^(b)+3/omega^(c) is equal to

Let a, b, and c be three real numbers satifying [(a, b, c)] [(1,9,7),(8,2,7),(7,3,7)]=[(0,0,0)] Let omega be a solution of x^(3)-1=0 with Im (omega) gt 0 . If a=2 with b and c satisfying (E), then the value of 3/omega^(a)+1/omega^(b)+3/omega^(c) is equal to

Let a,b, and c be three real numbers satistying [a,b,c][(1,9,7),(8,2,7),(7,3,7)]=[0,0,0] Let omega be a solution of x^3-1=0 with Im(omega)gt0. I fa=2 with b nd c satisfying (E) then the vlaue of 3/omega^a+1/omega^b+3/omega^c is equa to (A) -2 (B) 2 (C) 3 (D) -3

Let a,b, and c be three real numbers satistying [a,b,c][(1,9,7),(8,2,7),(7,3,7)]=[0,0,0] Let omega be a solution of x^3-1=0 with Im(omega)gt0. I fa=2 with b nd c satisfying (E) then the vlaue of 3/omega^a+1/omega^b+3/omega^c is equa to (A) -2 (B) 2 (C) 3 (D) -3

Let a,b, and c be three real numbers satistying [a,b,c][(1,9,7),(8,2,7),(7,3,7)]=[0,0,0] Let omega be a solution of x^3-1=0 with Im(omega)gt0. I fa=2 with b nd c satisfying (E) then the vlaue of 3/omega^a+1/omega^b+3/omega^c is equa to (A) -2 (B) 2 (C) 3 (D) -3

Let omega be a solution of z^3-1 = 0 If a = 2 , b=8 and c =7 then the value of 3/(omega^a) + 3/(omega^b) + 3/(omega^c) is equal to

(1- omega + omega^(2))^(7) + (1 + omega - omega^(2))^(7) =

Let p,q,r in R satisfies [p q r][(1,8,7),(9,2,3),(7,7,7)] = [0 0 0] .....(i) {:(,"List-I",,"List-I"),((P),"If the point M(p.q.r) with reference to (i) lies on the curve" 2x+y+z=1 then (7p+q+r) "is equal to",(1),-2),((Q),"Let" omega(ne1) "cube root of unity with" lm(omega) gt0.If p=2 "with q and r satisfying" (i) then (3/(omega^(p))+1/(omega^(q))+3/(omega^(r))) "is equal to ",(2),7),((R),"Let q=6 with p and r satisfying"(i). if alpha and beta "are roots of quadratic equation " px^(2)+qx+r=0 " then" Sigma_(n=0)^(oo) (1/(alpha)+1/(beta))^(n) " is equal to ",(3),6):}