The mean for a grouped data is calculated by `overlinex=a+(sumf_id_i)/(sumf_i)` .
What do the terms `'f_i'` and `'d_i'` represent in the above formula?

In the formula barx=a+((sumf_iu_i)/(sumf_i))xx h, u_i=

In the formula barx=a+((sumf_iu_i)/(sumf_i))xx h, u_i=

Given that barx=(sumf_ix_i)/(sumf_i) . Calculate barx if sumf_ix_i=760 and sumf_i =50

In Calculating the mean of grouped data, grouped in classes of equal width, we may use the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) Where, a is the assumed mean, a must be one of the mid point of the classes. Is the last statement correct? Justify your answer.

In Calculating the mean of grouped data, grouped in classes of equal width, we may use the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) Where, a is the assumed mean, a must be one of the mid point of the classes. Is the last statement correct? Justify your answer.

A.M. barx=A+(sumf_id_i)/(sumf_i) in this formulae A= ________

Mean barx=A+(sumf_id_i)/(sumf_i) .Find barx if A=29.5 sumf_id_i= -15 and sumf_i=25 .

In the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) for finding the mean of grouped data d_(i) 'S and deviation from a of

In the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) for finding the mean of grouped data d_(i) 'S and deviation from a of