`y dx - xdy + log x dx = 0`

The solution of y dx - x dy + log x dx = 0 is

Solution of the equation xdy – [y + xy^3 (1 + log x)] dx = 0 is :

Solution of the equation xdy – [y + xy^3 (1 + log x)] dx = 0 is :

Solution of the equation xdy – [y + xy^3 (1 + log x)] dx = 0 is :

Solve the following differential equation : xdy/dx + y = x log x, x!=0 .

xdy/dx + 2y = log x

Match the following {:(,"List-I",,"List-II",),((1),(x+2y^(3))(dy)/(dx)=y,(a),e^(tanx),),((2),cos^(2)x(dy)/(dx)+y = tanx,(b),(1)/(x),),((3),log x.(dy)/(dx)+(y)/(x) = sin 2x,(c),(1)/(y),),((4),ydx-xdy+log xdx = 0,(d),|log x|,),(,,(e),y,):}

y log y dx - x dy = 0

y log y dx - x dy = 0