Home
Class 12
PHYSICS
A short magnet of moment 6.75 Am^(2) pro...

A short magnet of moment `6.75 Am^(2)` produces a neutal point on its axis. If horizontal component of earth's magnetic field is `5xx10^(-5) "Wb"//m^(2)`, then the distance of the neutal point should be

Promotional Banner

Similar Questions

Explore conceptually related problems

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

A short bar magnet of magnetic moment 0,21 A - m^(2) is placed with its axis perpendicular to the direction of the horizontal component of the earth 's magnetic field .The distance of the point on the axis of the magnet from the centre of the magnet where the resultant magnetic field is inclined at 45^(@) with the horizontal component of the earth's field direction is (horizontal component of the earth's magnetic field 4.2xx10^(-5)

Angle of dip at a place is 30^(@) . If the vertical component of earth's magnetic field at that point is 7.5 xx 10^(-5) T, then the total magnetic field of earth at the point will be .

Angle of dip at a place is 30^(@) . If the vertical component of earth's magnetic field at that point is 7.5 xx 10^(-5) T, then the total magnetic field of earth at the point will be .

A short bar magnet is placed with its north pole pointing north. If magnetic moment of magnet is 0*4Am^2 and horizontal component of earth's magnetic field is 0*4 gauss, what is the distance of neutral point from the centre of the magnet?

A short bar magnet has magnetic moment 20 Am^2 . The axis of the magnet is in the magnetic meridian with the south pole pointing north. The horizontal component of earth's magnetic field at that place is 3 xx 10^-5 T. Find the point on the axis of the magnet at which the resultant magnetic field is zero, [such a point is called a neutral point].