`cos3x-sin2x=0.`

If cos^(3)x sin2x=sum_(r=0)^(n)a_(x)sin(rx),AA x in R then

3-2cos x-4sin x-cos2x+sin2x=0

Find the general solution for each of the following equations : (i) cos4x=cos2x (ii) cos3x=sin2x (iii) sin3x+cos2x=0 (iv) sinmx+sinnx=0

Solve cos3x+sin2x-sin4x=0 .

If 3sin x+3cos x=3+sin2x, x in[0,2 pi] then number of solution ( s) of given equation is

cos ^(3) x sin 2x = sum _(x =0) ^(n) ar sin (rx) AA x in R, then

cos ^(3) x sin 2x= sum _(x=0) ^(n) a _(r) sin (rx) AA x in R, then

Let A = {x in, R//|sqrt3 cos x - sin x| ge 2,0 le x le 2pi}.If x _(1) in A, x_(2) in A, then (x _(1))/(x _(2))=

a_1, a_2, a_3, in R-{0} and a_1+a_2cos2x+a_3sin^2x=0 for all x in R , then