`e=alpa-(1)/(2)beta t^(2)`, If temperature of cold junction is `0^(@)C` then temperature of inversion is (if `alpha = 500.0 muV//.^(@)C,beta=5.0 mu V//"Square".^(@)C`)

For a certain thermocouple , varepsilon=alphatheta+(1)/(2)betatheta^(@),where theta.^(@)C is the temperature of the hot junction and 0^(@)C is the temperature of the cold junction . If alpha =10 mu V.^(@)C^(-1) and beta=-(1)/(20)muV.^(@)C^(-2) , find the neutral temperature and temperature of inversion.

In a given thermocouple , the temperature of cold junction is 10^(@) C , while the temperature of inversion is 510^(@) C. What will be the neutral temperature?

In a thermocouple, temperature of the cold junction is 20^(@) C , the inversion of temperature is 600^(@) C then neutral temperature is

In a thermocouple the temperature of cold junction is 20^(@)C , while the temperature of inversion is 520^(@) C. At what temperature is the thermo emf maximum?

In a thermocouple , the temperature of cold junction is 30^(@) C and the neutral temperature is 310^(@) C . The temperature of inversion is

The temperature of the cold junction of thermo-couple is 0^(@)C and the temperature of hot junction is T^(@)C . The e.m.f . is E=16T-0.04 T^(2)mu volts. The temperature of inversion is

The temperature of the cold junction of thermo-couple is 0^(@)C and the temperature of hot junction is T^(@)C . The e.m.f . is E=16T-0.04 T^(2)mu volts. The temperature of inversion is

The temperature of the cold junction of thermo-couple is 0^(@)C and the temperature of hot junction is T^(@)C . The e.m.f . is E=16T-0.04 T^(2)mu volts. The temperature of inversion is

The thermo emf E of a thermocouple is found to vary wit temperature T of the junction (cold junction is 0^(@)C ) as E=40T-(T^(2))/(20) The temperature of inversion for the thermocouple is