A block of mass `m=1kg` moving on a horizontal surface with speed `v_(i)=2ms^(-1)` enters a rough patch ranging from `x0.10m to x=2.01m`. The retarding force `F_(r)` on the block in this range ins inversely proportional to x over this range
`F_(r)=-(k)/(x) fo r 0.1 lt xlt 2.01m`
`=0` for `lt 0.1m` and `x gt 2.01m` where `k=0.5J`. What is the final K.E. and speed `v_(f)` of the block as it crosses the patch?

A block of mass m= 1 kg , moving on a horizontal surface with speed v_(t)= 2 ms^(-1) enters a rough patch ranging from x= 0.10m" to "x= 2.01m . The retarding force F_(r ) on the block in this range is inversely proportional to x over this range, F_(r )= (-k)/(x)" for "0.1 lt x lt 2.01m = 0 " for "x lt 0.1m" and "x gt 2.01m where k= 0.5 J . What is the final kinetic energy and speed v_(f) of the block as it crosses this patch?

A block of mass m= 1 kg , moving on a horizontal surface with speed v_(t)= 2 ms^(-1) enters a rough patch ranging from x= 0.10m" to "x= 2.01m . The retarding force F_(r ) on the block in this range is inversely proportional to x over this range, F_(r )= (-k)/(x)" for "0.1 lt x lt 2.01m = 0 " for "x lt 0.1m" and "x gt 2.01m where k= 0.5 J . What is the final kinetic energy and speed v_(f) of the block as it crosses this patch?