At time `t = 0,` a car moving along a straight line has a velocity of `16 ms^-1.` It slows down with an acceleration of `-0.5t ms^-2,` where t is in second. Mark the correct statement (s).

At time t=0 s a car passes a point with velocity of 16 m//s and thereafter slows down with acceleration a=-0.5t m//s^(2) ,where t is in seconds. It stops at the instant t=

At time t=0 s a car passes a point with velocity of 16 m//s and thereafter slows down with acceleration a=-0.5t m//s^(2) ,where t is in seconds. It stops at the instant t=

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-

A particle starts from rest at t=0 and moves along a straight line with a variable acceleration given by a (t)=(3t+1)ms^(-2) ,where t],[ is in seconds.The velocity of the particle at t=4s is

If a particle is moving along a straight line and following is the graph showing acceleration varying with time then choose correct statement(s). At t=0, x=0 and v_(0)=7 ms^(-1)

Acceleration time graph of a particle moving along a straight line is given. Then average acceleration between t=0 & t=4 is :-

Acceleration time graph of a particle moving along a straight line is given. Then average acceleration between t=0 & t=4 is :-

Acceleration time graph of a particle moving along a straight line is given. Then average acceleration between t=0 & t=4 is :-