On dissolving `0.25 g`of a non-volatile substance in`30 mL` benzene `(density 0.8 g mL^(-1))`, its freezing point decreases by `0.25^(@)C` . Calculate the molecular mass of non-volatile substance `(K_(f) = 5.1 K kg mol^(-1))`.

On dissolving 0.25 g of a non-volatile substance in 30 mL of benzene (density 0.8 g "mol"^(-1) ) its freezing point decreases by 0.40^(@)C . Calculate the molecular mass of the non-volatile substance. ( K_(f) for benzene is 5.12 k m^(-1) )

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 K kg mol ^(-1))

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 ^(@)C kg mol ^(-1))

By dissolving 13.6 g of a substance in 20 g of water, the freezing point decreased by 3.7^(@)C . Calculate the molecular mass of the substance. (Molal depression constant for water = 1.863K kg mol^(-1))

By dissolving 13.6 g of a substance in 20 g of water, the freezing point decreased by 3.7^(@)C . Calculate the molecular mass of the substance. (Molal depression constant for water = 1.863K kg mol^(-1))

By dissolving 13.6 g of a substance in 20 g of water, the freezing point decreased by 3.7^(@)C . Calculate the molecular mass of the substance. (Molal depression constant for water = 1.863K kg mol^(-1))

A solution of 0.643 g of an organic compound in 50 mL of benzene (density 0.879 g//mL ) lowered its freezing point from 5.51^(@)C to 5.03^(@)C . Calculate the molecular weight of solid. (K_(f) for benzene is 5.12 K mol^(-1) kg )