The ionization potential of hydrogen atom is 13.6 eV. The wavelength of the energy radiation required for the ionization of H-atom

If the ionisation potential for hydrogen atom is 13.6 eV, then the wavelength of light required for the ionisation of hydrogen atom would be:

The ionization potential of a hydrogen atom is 13.6 eV. What will be the energy of the atom corresponding to n=2?

If the ionization potential of hydrogen atom is 13.6 V, its energy in the n = 3 is approximately

The ionization potential for hydrogen atom is 13.6 eV , the ionization potential for He^(+) is

The ionization potential of hydrogen atom is 13.6 eV. The energy required to remove an electron from the n=2 state of hydrogen atom is:

If the ionization potential of hydrogen atom is 13.6eV , the energy required to remove from the third orbit of hydrogen atom is k//2eV . Find the value of k …….

If the ionization potential of hydrogen atom is 13.6eV , the energy required to remove from the third orbit of hydrogen atom is k//2eV . Find the value of k …….