The linear mass density of a thin rod AB of length L varies from A to B as `lambda (x) =lambda_0 (1 + x/L)`. Where x is the distance from A. If M is the mass of the rod then its moment of inertia about an axis passing through A and perpendicualr to the rod is :

The linear density of a thin rod of length 1m lies as lambda = (1+2x) , where x is the distance from its one end. Find the distance of its center of mass from this end.

The linear density of a thin rod of length 1m lies as lambda = (1+2x) , where x is the distance from its one end. Find the distance of its center of mass from this end.

A thin rod AB of length a has variable mass per unit length rho_(0) (1 + (x)/(a)) where x is the distance measured from A and rho_(0) is a constant. Find moment of inertia of the rod about an axis passing through A and perpendicular to AB.

The linear mass density of a rod of length 2L varies with distance (x) from center as lambda=lambda_(0)(1+(x)/(L)) .The distance of COM from center is nL.Then n is

Moment of inertia of a thin rod of mass m and length l about an axis passing through a point l/4 from one end and perpendicular to the rod is

Moment of inertia of a thin rod of mass m and length l about an axis passing through a point l/4 from one end and perpendicular to the rod is

Linear mss density (mass/length) of a rod depends on the distanec from one end (say A) as lamda_(x)=(alphax+beta) here alpha and beta are constants, find the moment of inertia of this rod about an axis passing through A and perpendicular to the rod. Length of the rod is l .

Linear mss density (mass/length) of a rod depends on the distanec from one end (say A) as lamda_(x)=(alphax+beta) here alpha and beta are constants, find the moment of inertia of this rod about an axis passing through A and perpendicular to the rod. Length of the rod is l .

The moment of inertia of thin rod of linear density lambda and length l about an axis passing through one end and perpendicular to its length is