The line joining `A(bcosalphabsinalpha)` and `B(acosbeta,asinbeta)` is produced to the point `M(x ,y)` so that `A M` and `B M` are in the ratio `b : adot` Then prove that `x+ytan(alpha+beta/2)=0.`

The line joining A(bcosalpha,bsinalpha) and B(acosbeta,asinbeta) is produced to the point M(x ,y) so that A M and B M are in the ratio b : adot Then prove that x+ytan((alpha+beta)/2)=0.

The line joining A(b cos alpha b sin alpha) and B(a cos beta,a sin beta) is produced to the point M(x,y) so that AM and BM are in the ratio b:a. Then prove that x+y tan(alpha+(beta)/(2))=0

The line joining A(bcosalpha,bsinalpha) and B(acosbeta,asinbeta) is produced to the point M(x ,y) so that A M and B M are in the ratio b : adot Then xcos((alpha+beta)/2)+ysin((alpha+beta)/2)

The line joining A(bcosalpha,bsinalpha)andB(acosbeta,asinbeta) is produced to the point M(x,y) such that overline(AM):overline(BM)=b:a , prove that x+y"tan"(alpha+beta)/(2)=0 .

The line joining A (b cos alpha, b sin alpha ) and B (a cos beta, a sin beta) , where a ne b , is produced to the point M(x,y) so that AM :MB = b :a Then xcosfrac(alpha+beta)(2)+ysinfrac(alpha+beta)(2)

The line joining A (b cos alpha b sin alpha ) and B (a cos beta , a sin beta ) , where a ne b , is produced to the point M(x , y) so that AM : BM = b : a . Then x "cos" (alpha+beta)/(2)+ y "sin" (alpha+beta)/(2) is equal to _

Line joining A(b cos alpha,b sin alpha) and B(a cos beta,a sin beta), is produced to the point M(x,y) such that AM:MB=b:a then x cos((alpha+beta)/(2))+y sin((alpha+beta)/(2))=

Distance between the points A(acosalpha, "asin alpha) and B(acosbeta," asinbeta) is equal to

A point (-4,1) divides the line joining A(2,-2) and B(x,y) in the ratio 3:5. Then point B is