The least count of an istrument is `0.01cm`. Taking all precautions, the most possible error in the measurement can be

In an experiment of simple pendulum, time period measured was 50s for 25 vibrations when the length of the simple pendulum was taken to be 100cm . If the lest count of stop watch is 0.1s and that of metre scale is 0.1 cm , calculate the maximum possible percentage error in the measurement of value of g .

The least count of a vernier callipers is 0.01 cm. Then, the error in the measurement is

The least count of a vernier callipers is 0.01 cm. Then, the error in the measurement is

The side of a cube, as measured with a vernier calipers of least count 0.01 cm is 3.00 cm. The maximum possible error in the measurement of volume is

The side of a cube, as measured with a vernier calipers of least count 0.01 cm is 3.00 cm. The maximum possible error in the measurement of volume is

The side of an object measured by means of a vernier callipers is 3.52 cm. If the least count of the vernier is 0.01 cm,estimate the percentage error in the measurement.

In Searle's apparatus diameter of the wire was measured 0.05 cm by screw gauge of least count 0.001 cm. The length of wire was measured 110 cm by meter scale of least count 0.1 cm. An external load of 50 N was applied. The extension in length of wire was measured 0.125 cm by micrometer of least count 0.001 cm. Find the maximum possible error in measurement of Young's modulus.

The dimensions of a rectangular block measured with vernier callipers having least count of 0.01 cm are 5 mm xx 10 mm xx 5 mm. What is the maximum percentage error in the measurement of the volume of the block?