`DeltaABC` and `DeltaBDE` are two equilateral triangles. If `D` is the mid-point of `BC`, then the ratio of the areas of `DeltaABC` and `DeltaBDE` is

DeltaABC and DeltaBDE are two equilateral triangles such that D is the midpoint of BC. Ratio of the areas of triangles DeltaABC and DeltaBDE is

DeltaABCandDeltaCDE are two equilateral triangles such that D is the mid -point of BC . The ratio of the areas of DeltaCDEandDeltaABC is 1 : k then k =

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Ratio of the areas of triangles ABC and BDE is

ABC and BDF are two equilateral triangles such that D is the mid -point of BC. Ratio of the areas of triangles ABC and BDF is

triangleABC and triangleDEF are two equilateral triangle such that D is the mid point of BC.The ratio of the areas of triangle ABC and BDE is

Tick the correct answer and justify : ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Ratio of the areas of triangles ABC and BDE is