If the ionization potential of hydrogen atom is 13.6 V, its energy in the n = 3 is approximately

The ionization potential of the hydrogen atom is 13.6 V. The energy needed to ionize a hydrogen atom which is in its first excited state is about

The ionization potential of a hydrogen atom is 13.6 eV. What will be the energy of the atom corresponding to n=2?

Ionization potential of hydrogen atom is 13.6 V . Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV . The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

Ionization potential of hydrogen atom is 13.6 V . Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV . The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

Ionization potential of hydrogen atom is 13.6 V . Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV . The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

Ionization potential of hydrogen atom is 13.6 V . Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV . The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

Ionization potential of hydrogen atom is 13.6 V . Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV . The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

The ionization potential of hydrogen atom is 13.6 eV. The wavelength of the energy radiation required for the ionization of H-atom

The ionization potential of hydrogen atom is 13.6 eV. The energy required to remove an electron from the n=2 state of hydrogen atom is: