An organic compound 'A' is oxidized with `Na_(2)O_(2)` followed by boiling with `HNO_(3)`. The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate. Based on above observation,the element present in the given compound is `:`

In qualitive analysis, an organic compound 'A' is heated with dry CuO ,CO_(2) gas is liberated and H_(2)O is formed . The same compound 'A' when heated with Na_(2) O_(2) , followed by boiling with HNO_(3) and ammonium molybdate gives yellow precipitate. Based on the tests, the elements present in compound 'A' are __________.

A compound X react with Na_(2)O_(2) and forms Y , Y is reacted with nitric acid and then treated with ammonium molybdate to give yellow ppt.

A compound X react with Na_(2)O_(2) and forms Y , Y is reacted with nitric acid and then treated with ammonium molybdate to give yellow ppt.

An organic compound is fused with fusion mixture and extracted with HNO_3 .The extract gives yellow precipitate with ammonium molybdate. It shows the presence of which element :

On being heated with conc. HNO_(3) and ammonium molybdate solution, the salt solutions gives a yellow precipitate. The salt(s) may be

When a mixture containing phosphate is heated with conc. HNO_(3) and ammonium molybdated solution, a canary yellow precipitate is formed . The formula of the yellow precipitate is