If A, B, C are collinearpoints such that A(3,4), C(11,10) and AB = 2.5 then point B is

If A & B are the points (-3,4)a n d(2,1) , then the co-ordinates of the point C on AB produced such that A C=2B C are: a. (2,4) b. (3,7) c. (7,-2) d. (1/2,5/2)

If A(3, 2, -4), B(5, 4, -6) and C(9, 8, -10) are three collinear points, then the ratio in which point C divides AB.

If A(3, 2, -4), B(5, 4, -6) and C(9, 8, -10) are three collinear points, then the ratio in which point C divides AB.

Points A,B and C are collinear.Point B is the mid-point of the line segment AC.Point D is not collinear with the other points.DA=DB and DB=BC=10. What is the length of DC?

If A&B are the points (-3,4) and (2,1), then the co-ordinates of the point C on AB produced such that AC=2BC are: (2,4)b(3,7)c.(7,-2)d*(-(1)/(2),(5)/(2))

Consider the points A(3,2,4), B(5,8,0( and C(4,5,2). Using only distance formula prove that A, B and C are collinear. Also prove that C is the mid point of AB.

Three vector a, b and c are such that abs(a)=1, abs(b)=2, abs(c)=4" and "a+b+c=0 . Then the value of 4a.b+3b.c+3c.a is equal to