A gaseous hydrocarbon on complete combustion gives 3.38 g of `CO_(2)` and 0.690 g of `H_(2)O` and no other product. The empirical formula of the hydrocarbon is

Two different formulas are used in order to represent composition of any miolecule, empirical formula and molecular formula . While the fomer gives an idea of relative ratio of number of atoms, latter gives the exact number of atoms in the molecule. 4.6 gm of an organic compound on complete combustion gave 8.8 gm of CO_(2)(g) and 5.4 gm of H_(2)O(g) only and no other products . what will be the empirical formula of the hydrocarbon?

4 g of a hydrocarbon on complete combustion gave 12.571 g of Co, and 5.143 g of water. What is the empirical formula of the hydrocarbon?

4.4 gms of a hydrocarbon on complete combustion produced 13.2 gms of CO_(2) and 7.2 gms of H_(2)O . What is the hydrocarbon?

4.4 gms of a hydrocarbon on complete combustion produced 13.2 gms of CO_(2) and 7.2 gms of H_(2)O . What is the hydrocarbon?

4.4 gms of a hydrocarbon on complete combustion produced 13.2 gms of CO_(2) and 7.2 gms of H_(2)O . How many moles of oxygen is consumed per mole of hydrocarbon in the combustion?