The self inductance of a toroid is :-

A toroid is wound over a circular core. Radius of each turn is r and radius of toroid is R(>>r). The Coefficient of self - inductance of the toroid is given by

A toroidal solenoid with an air core has an average radius of 15 cm , area of cross-section 12 "cm"^(2) and 1200 turns . Ignoring the field variation across the cross-section of the toroid the self-inductance of the toroid is

A toroidal solenoid with air core has an average radius of 15cm, area of cross section 12cm^(2) and has 2000 turns. Calculate the self- inductance of the toroid. Assume the field to be uniform across the cross-section of the toroid.

Find the self-inductance of a toroidal solenoid of radius 20 cm, area of cross section 100 cm^(2) and having 500 turns. Assume that the field variations across the cross section of the toroid are negligible. Further, if a secondary coil of 300 turns is wound on this toroid and the current in the primary coil is increased from 2 A to 5 A in 0.05 s. Find the emf induced in the secondary coil.

A toroid is wound over a circular core. Radius of each turn is r and radius of toroid is R (gt gt r) . The coefficient of self-inductance of the toroid is given by

A toroid is wound over a circular core. Radius of each turn is r and radius of toroid is R (gt gt r) . The coefficient of self-inductance of the toroid is given by

(a) A toroidal solenoid with an air core has an average radius of 0.15m, area of cross section 12 xx 10^(-4) m^(2) and 1200 turns. Obtain the self inductance of the toroid. Ignore field variation across the cross section of the toroid. (b) A second coil of 300 turns is wound closely on the toroid above. If the current in the primary coil is increased from zero to 2.0 A in 0.05 s, obtain the induced emf in the secondary coil.